Question

formula of cubic polynomial whose zeroes are given

Answer 1

bhai teeni zeros ko multiply kar de
jaise ager tere pass zeros hain 2, 6,8
to (x-2)(x-6)(x-8)

Answer 2

Answer:

$k ( {x}^{3} - ( \alpha + \beta + \gamma ) + (\alpha \beta + \beta \gamma + \alpha \gamma ) - \alpha \beta \gamma )$

Step-by-step explanation:

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