Forn a quadratic polynomial whose zeroes are 3+√5/2 nd 3-√5/2?
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Answered by
5
Sum of zeroes = 3 + underoot 5 /2 + 3- underoot 5/2
= 3 + 3
= 6
product of zeroes = 3 + underoot 5 /2 * 3- underoot 5/2
= (3)2 - (underoot 5/2)2
= 9 - 5/4
= 9-5/4
= 4/4
= 1
Quadratic polynomial =
x² - 6 + 1 is the required polynomial.
= 3 + 3
= 6
product of zeroes = 3 + underoot 5 /2 * 3- underoot 5/2
= (3)2 - (underoot 5/2)2
= 9 - 5/4
= 9-5/4
= 4/4
= 1
Quadratic polynomial =
x² - 6 + 1 is the required polynomial.
lasya91020:
It's 3+√5 nd not 5+2√3!!
Answered by
3
Answer: x^2-3x+1
Step-by-step explanation:
Sum= 3+√5/2+3-√5/2=3
Product 3+√5/2×3-√5/2=1
K(x^2-(Sum)x+Product)
K(x^2-(3)x+1
K=1, x^2-3x+1
So x^2-3x+1 is the required quadratic polynomialpolynomialpolynomial
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