Math, asked by lasya91020, 1 year ago

Forn a quadratic polynomial whose zeroes are 3+√5/2 nd 3-√5/2?

Answers

Answered by Shivaya1
5
Sum of zeroes = 3 + underoot 5 /2 + 3- underoot 5/2
= 3 + 3
= 6

product of zeroes = 3 + underoot 5 /2 * 3- underoot 5/2
= (3)2 - (underoot 5/2)2
= 9 - 5/4
= 9-5/4
= 4/4
= 1

Quadratic polynomial = 

x² - 6 + 1 is the required polynomial.

lasya91020: It's 3+√5 nd not 5+2√3!!
lasya91020: hmm
lasya91020: will u pls answer it again
lasya91020: okay
Answered by GuyAGuyAguy
3

Answer: x^2-3x+1

Step-by-step explanation:

Sum= 3+√5/2+3-√5/2=3

Product 3+√5/2×3-√5/2=1

K(x^2-(Sum)x+Product)

K(x^2-(3)x+1

K=1, x^2-3x+1

So x^2-3x+1 is the required quadratic polynomialpolynomialpolynomial

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