foue point masses each of mass m are placed at the corner of square of side a . the magnitude of gravitional force expercienced by each particle is
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Consider the situation shown in the below figure.
Let the square is ABCD and its centre (intersecting point is O) then the centre is equidistant from all corners. So the magnitude of force due to mass at each corner on the mass at centre is same.
From the figure we can observe that,
FOA & FOD are opposite to each otherandFOB & FOC are opposite to each other
So the net force on the mass m at the centre becomes zero.
Hope this information will clear your doubts about the topic.
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