Math, asked by daku59, 11 months ago

Four bells commence tolling together and toll at intervals of 2.3.6 and
S seconds respectively. In 90 minutes, how many times do they toll together?step by step statement

Answers

Answered by rajeevgupta39
2

Step-by-step explanation:

simplify calculation lets make the denominator same

so now we have 

4/4

11/4

22/4 and 

13/4

LCM of 4,11,22,13 is 572

so the bells will rang together after 572/4 seconds i.e after 143 seconds

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Vaduz Ace

Answer: 2 minute 23 seconds.

Step-by-step explanation:

bells toll at intervals of 1, 11/4,11/2,13/4 seconds.

they will toll again after,

L.C.M. of ( 1, 11/4,11/2,13/4 seconds. )

to simplify calculation lets make the denominator equal.

so now we have

4/4, 11/4, 22/4 and 13/4

LCM of 4,11,22,13 is 572

so the bells will rang together after 572/4 seconds i.e after 143 seconds or 2 minute 23 seconds.

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Answered by mlilyhepsiba
2

Answer:

Step-by-step explanation :

Intervals at which 4 bells toll together=2,3,6

We have to find LCM of 2,3,6-

L.C.M = 6

Now divide 6 by 90 minutes,. 6/90 or 6/5400 sec

We obtain 1/900

So 900/4=225 times-1 = 224

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