solve this question by elimination method
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5p+1q=2
6p-3q=1
Step-by-step explanation:
eqn no. 1 × 3 = 15p+3q=6
15p+3q=6
6p-3q=1
adding we get 21p= 7
p=1by3
put 1by3 in eqn no. 2
6×1by3-3q=1
2-3q=1
-3q=-1
q=1by3
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hope it helps you
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