Question

Four bells ring at interval 6, 12, 18, 24 seconds. They starts ringing simultaneously at 8 o'c clock. When will they ring again together:

Answer 1

by taking lcm of 6,12,18,24
we get 72 sec
they ring again together at 8:01:12
hope you got it if any doubt ask tq

Answer 2

Answer: The bells will ring again together  at 8:01:12

Step-by-step explanation:

By prime factorisation method we have

$6= 2^1\times 3^1$

$12= 2^2 \times 3$

$18= 2\times 3^2$

$24= 2^3 \times 3$

L.C.M.= $2^3 \times 3^2 =72$

Therefore they will ring together after 72 seconds

Hence, the bells will ring again together at 8:01:12