Four bells rings at an interval of 6, 8, 12 and 20 minutes. If they ring
simultaneously at 8 a.m. then when will theyring simultaneously again?
Answers
Answered by
1
Answer:
10 am
Step-by-step explanation:
The LCM of 6,8,12 and 20 = 120 minutes = 2 hours
Therefore 2 hours after 8 am = 10 am
Answered by
3
Answer:
10 am
Step-by-step explanation:
Find the prime factors of the 4 intervals:
6 = 2 x 3
8 = 2³
12 = 2² x 3
20 = 2² x 5
Find the LCM of these 4 intervals:
LCM = 2³ x 3 x 5 = 120
⇒ They will ring together again after 120 mins
Find the next time they will ring together again:
120 mins = 2 hours
8 am + 120 mins = 8am + 2 hours
8 am + 120 mins = 10 am
Answer: 10 am
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