Four capacitors 4 µF, 6mu * F, 5mu * F, 3mu * F are connected in seri to a source of 150V. The potential difference in volt, acro the 5mu * F capacitor will be
a. 30 volt c. 50 volt b. 40 volt d. 60 volt
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Answered by
57
Answer:
Correct option is
D
60
Given : C
1
=3μF C
2
=6μF C
3
=6μF
Equivalent capacitance for series combination
C
eq
1
=
C
1
1
+
C
2
1
+
C
3
1
C
eq
1
=
3
1
+
6
1
+
6
1
⟹C
eq
=1.5μF
Thus the charge flowing through the circuit q=C
eq
V
q=1.5μF×120 volt =180μC
Potential difference across 3μF, V
1
=
C
1
q
=
3μF
180μC
=60 volt
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0
Explanation:
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