CBSE BOARD XII, asked by priyansh9397, 23 hours ago

Four capacitors 4 µF, 6mu * F, 5mu * F, 3mu * F are connected in seri to a source of 150V. The potential difference in volt, acro the 5mu * F capacitor will be
a. 30 volt c. 50 volt b. 40 volt d. 60 volt​

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Answers

Answered by mayajadhavbnn
57

Answer:

Correct option is

D

60

Given : C

1

=3μF C

2

=6μF C

3

=6μF

Equivalent capacitance for series combination

C

eq

1

=

C

1

1

+

C

2

1

+

C

3

1

C

eq

1

=

3

1

+

6

1

+

6

1

⟹C

eq

=1.5μF

Thus the charge flowing through the circuit q=C

eq

V

q=1.5μF×120 volt =180μC

Potential difference across 3μF, V

1

=

C

1

q

=

3μF

180μC

=60 volt

Answered by kashifzubair82
0

Explanation:

बेक़हह छि मये बोज़ रात मांज़ बहथ तस ओस बेगस छु अख व बा हमान रोज़ ओल र बा छस यज़हान पज़े सहु शहर पसंद फ़लम पसंद यो छु मये

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