Four capacitors, C-6uF, C₂-4μF, C-8μF and C-12µF are fully charged and there is no charge transfer between the capacitors. Before S is closed, initial charge of C is 80 C. What is the charge of C, after S is closed?
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Answer:
C
1
=3μF C
2
=6μF C
3
=6μF
Equivalent capacitance for series combination
C
eq
1
=
C
1
1
+
C
2
1
+
C
3
1
C
eq
1
=
3
1
+
6
1
+
6
1
⟹C
eq
=1.5μF
Thus the charge flowing through the circuit q=C
eq
V
q=1.5μF×120 volt =180μC
Potential difference across 3μF, V
1
=
C
1
q
=
3μF
180μC
=60 volt
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