Question

four cells each of EMF 1.5 volt and internal resistance 0.5 ohm are connected in series but one cell is wrongly connected the network is and the net internal resistance between a and b is? ​

Answer 1

The net internal resistance between a and b is 3 A

Explanation:

Here 4 cells each having emf

e  =  1.5  V

and internal resistance

r  =  0.25  Ω

are connected in series. So total resistance of the circuit will be

4 ⋅ r  =   4   =  0.25 =  1 Ω

As one of the cell is connected in reverse direction the effective emf becomes

E  =  3 ⋅ e − e = 2 e   = 2  x  1.5 = 3  V

Hence current in the circuit

I  =  net emf

Total resistance  =  3  x 1 =  3  A

Thus the net internal resistance between a and b is 3 A

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