Question

Four cells each of emf 1.9 V and in internal resistance 1 ohm are connected to an external resistance of 18 ohm .Find the terminal p.d of this combination.

Ans : 10.8 V

Answer 1

hope it is helpful for you

Answer 2

Hey mate!

Here's your answer!!

The potential difference is = 3.69V

Explanation:
We apply the equation,

U = RI
E - U = rI
E = (R + r) I

The emf is E = 2• 1.9 = 3.8V

The cells are in series-parallel and the internal resistances as well.

The total resistance is,
$r + r = \frac{1}{2} + \frac{1}{2} + 18 = 19$
The current is,
$i \: = \frac{3.9}{19} = 0.21a$
So, the potential difference is,
= U = 18• 0.21 = 3.69V.

$hope \: it \: helps \: you.$
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