Four cells, each of internal resistance 1ohm,are connected in parallel.the battery resistance will be
Answers
Answered by
2
the resistance of battery R=1÷4=0.25
Answered by
5
The cells are connected in parallel
Hence,
1/Rp = 1/R1 + 1/R2 + 1/R3 + 1/R4
1/Rp = 1/1 + 1/1 + 1/1 + 1/1
1/Rp = 4/1
Rp = 1/4
Rp = 0.25
therefore, The battery resistance will be 1/4
Hence,
1/Rp = 1/R1 + 1/R2 + 1/R3 + 1/R4
1/Rp = 1/1 + 1/1 + 1/1 + 1/1
1/Rp = 4/1
Rp = 1/4
Rp = 0.25
therefore, The battery resistance will be 1/4
kvnmurty:
Good
Similar questions