Physics, asked by priyanshugarg5480, 11 months ago

Four charges ????₁= 2 × 10⁻⁸ C, ????₂ = -2 x 10⁻⁸ C,
????₃ = = -3 x 10⁻⁸ C, and q₄ = 6 x 10⁻⁸ C are placed
at four corners of a square of side √2 m. What
is the potential at the centre of the square?
(a) 270 V (b) 300 V
(c) Zero (d) 100 V

Answers

Answered by sweetybee
1

Answer:

so the ans is option a )270v

Explanation:

hope it helps you....

Attachments:
Answered by hemant9999
0

Explanation:

using formula V=KQ/R

V(net)=K/R(Q1+Q2+Q3+Q4)

V=K/R(3×10^-8)

V=9×10^9 × 3×10^-8÷1

V=270Volts

Similar questions