four charges are placed at the corners of a square of side 'a' in the fig. find the net force on the charge at the corner C
Answers
using parallelogram law ,
we studied in first year
Rvector=rootof a^2+b^2+2abcosthetta
Net force = (k q²/d²) ( √2 + 1/2) Direction from C to A
Explanation:
F = k q₁(q₂)/r²
r = Distance between Charges
q₁ , q₂ are charges
d = Distance between them
Repulsive force if same sign between charges
Attractive force if opposite sign between charges
k = 1/4π∈₀ = 9.0 x 10⁹ N·m²/C²
Force by D on C attractive Force
= k q²/d² ( Direction from C to D)
Force by B on C attractive Force
= k q²/d² ( Direction from C to B)
Force by A on C attractive Force
= k q²/(d√2)² ( Direction from C to A)
= k q²/2d² ( Direction from C to A)
Net Force of k q²/d² ( Direction from C to D) & k q²/d² ( Direction from C to B)
= √ (k q²/d²)² + ( k q²/d²)²
=√2 . k q²/d²
net force on the charge at the corner C = k q²/2d² + √2 . k q²/d²
= (k q²/d²) ( √2 + 1/2) Direction from C to A
Learn more:
Three charges each of magnitude q are placed at the corners of an ...
https://brainly.in/question/9430181
Four point charges +5 mC, +2 mC, +10mC and +2 mC are kept at ...
https://brainly.in/question/10140634
Five point charges each of charge q are placed on five vertices of ...
https://brainly.in/question/8863174