Question

Four children A, B, C and D divide a bag of sweets. A takes ⅓ of them, B takes 2/5
of the remaining and the rest is shared equally between C and D. What fraction of
the sweets did C get?​

Answer 1

Let the total number of sweets = X

Then A takes 1/3*X=X/3

Then B takes 2/5*X =2x/5

Then the sum = X/3+2x/5=11x/15

Since to find the number of sweets that C and D has equally shared then,

X/1-11x/15=4x/15

4x/15÷2

4x/15*1/2 =4x/30

Then 2x/15 is the number of sweets that C get

Answer 2

Answer:

Given,

A's portion= 1/3 of the total.

B's portion= 2/5 of the remaining.

C's portion= 1/2 of the remaining.

D's portion= 1/2 of the remaining.

To Find,

Fraction of the sweets taken by C.

Assumption,

Let us assume, the total number of sweets in the bag = 15x.

Solution,

We have a total of 15x sweets,

A takes 1/3 of them, leaving 10x sweets and taking 5x sweets.

Then B takes 2/5 out of 10x sweets.

So, B takes 4x sweets leaving 6x.

6x sweets are remaining, which are equally distributed amongst C and D.

Therefore, C and D get 3x sweets each.

The fraction of sweets taken by C= sweets taken by C/ total sweets.

= 3x/15x= 1/5.

Hence, the fraction of the sweets taken by C is 1/5.