Question

Four children shared the prize of P12,000 in the ratio of 6:4:3:3. What is the largest and smallest shares?

Answer 1

Answer:

Given:-

Four children shared the prize of P12,000 in the ratio of 6:4:3:3.

To find:-

the largest and smallest shares

Solution:-

Let the shares be 6x,4x,3x,3x

ATQ

$\qquad\quad\displaystyle\sf {:}\longrightarrow 6x+4x+3x+3x=12000$

$\qquad\quad\displaystyle\sf {:}\longrightarrow 10x+6x=12000$

$\qquad\quad\displaystyle\sf {:}\longrightarrow 16x=12000$

$\qquad\quad\displaystyle\sf {:}\longrightarrow x=\dfrac {12000}{16}$

$\qquad\quad\displaystyle\sf {:}\longrightarrow x=750$

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$\qquad\quad\displaystyle\sf {:}\longrightarrow 6x=6×750=4500$

$\qquad\quad\displaystyle\sf {:}\longrightarrow 4x=4×750=3000$

$\qquad\quad\displaystyle\sf {:}\longrightarrow 3x=3×750=2250$

Here

$\qquad\quad\displaystyle\sf {:}\longrightarrow 4500>3000>2250$

Hence

• The first child has largest share.
• The third and fourth children have smallest share.