Question

Four coins are tossed, find the probability of getting atleast 2 Tails.

Answer 1

Hey mate here is you answer:-
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SOL..: let 'S' be the sample space.
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. s=(TTTT, TTTH, TTHT, THTT, HTTT, HHHH, HHHT, HHTH, HTHH, THHH)
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therefore, n(s)=10.
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EVENT :A--
getting at least 2 tail.
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.: A=(TTTT, TTTH, TTHT, THTT, HTTT)
hence,
n(A)=5....
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THE PROBABILITY OF THAT EVENT..
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P(A)=n(A)/n(s)
= 5/10
= 1/2.
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I Hope it will help you dear mate.
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plz mark as the Brainliest..
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thanks for asking your doubt here.
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thanks!!!!!!

Answer 2

You have 4 coins and each coin gives 2 outcomes so you have 2x2x2x2 outcomes (16)

now for at least two tails, you need those which have 2,3 and 4 tails in them so...

well, I can't really put in words my answer so I might as well just give you the sample space,

THHT
THTH
HTHT
TTTT
HHTT
HTTH
TTHH
TTTH
TTHT
THTT
HTTT



11/16


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