Four coins are tossed simultaneously what is the probability of getting (i) 2 heads (ii) 3 heads (iii) atleast 3 heads
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Probability of getting 2 heads is 1 . 3heads is 3/2.atleast 3heads is also 3/2
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Hi
If 4 coins are tossed total possible
outcomes are
HHHH , HHHT , HHTH , HHTT
HTHH , HTHT , HTTH , HTTT
THHH , THHT, THTH , THTT
TTHH , TTHT , TTTH , TTTT
Where H indicates head ,and
T a tail .
Number of total possible
outcomes = 16 ---( 1 )
i ) getting 2 heads :
Favorable outcomes = { HHTT,
HTHT , HTTH , THHT , THTH ,
TTHH }
Number of favourable
outcomes = 6 ---( 2 )
P( getting 2 heads ) = ( 2 )/( 1 )
= 6/16
=3/8
ii ) getting 3 heads :
Favorable outcomes = { HHHT ,
HHTH , HTHH , THHH }
Number of favourable
outcomes = 4 ---( 3 )
P( getting 3 heads ) = ( 3 )/( 1 )
= 4/16
= 1/4
iii ) getting at least 3 heads :
Favourable outcomes = { HHHH ,
HHHT , HHTH , HTHH, THHH }
Number of favourable
outcomes = 5 ---( 4 )
P( at least 3 heads ) = ( 4 )/( 1 )
= 5/16
I hope this helps you.
: )
If 4 coins are tossed total possible
outcomes are
HHHH , HHHT , HHTH , HHTT
HTHH , HTHT , HTTH , HTTT
THHH , THHT, THTH , THTT
TTHH , TTHT , TTTH , TTTT
Where H indicates head ,and
T a tail .
Number of total possible
outcomes = 16 ---( 1 )
i ) getting 2 heads :
Favorable outcomes = { HHTT,
HTHT , HTTH , THHT , THTH ,
TTHH }
Number of favourable
outcomes = 6 ---( 2 )
P( getting 2 heads ) = ( 2 )/( 1 )
= 6/16
=3/8
ii ) getting 3 heads :
Favorable outcomes = { HHHT ,
HHTH , HTHH , THHH }
Number of favourable
outcomes = 4 ---( 3 )
P( getting 3 heads ) = ( 3 )/( 1 )
= 4/16
= 1/4
iii ) getting at least 3 heads :
Favourable outcomes = { HHHH ,
HHHT , HHTH , HTHH, THHH }
Number of favourable
outcomes = 5 ---( 4 )
P( at least 3 heads ) = ( 4 )/( 1 )
= 5/16
I hope this helps you.
: )
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