Question

Four consecutive integers have a sum of 150

Answer 1

Step-by-step explanation:

let the 4 consecutive integers be x , x +1 , x+2 , x+3.

According to the problem

x+x+1+x+2+x+3= 150

4x + 6 = 150

4x = 150 -6

4x = 144.

x = 36

x+1 = 36 +1 = 37

x+2 = 36 +2 = 38

x+3 = 36 +3 = 39.

Answer 2

Answer:

The four consecutive integers = 38,39,40,41

Step-by-step explanation:

Let the consecutive integers be : x,x+1,x+2,x+3

x+x+1+x+2+x+3 = 150

4x + 6 = 150

4x = 150 - 6

4x = 144

x = 144/4

x = 38

Therefore, 1st consecutive integer = x

= 38

2nd consecutive integer = x + 1

= 38 + 1

= 39

3rd consecutive integer = x + 2

= 38 + 2

= 40

4th consecutive integer = x + 3

= 38 + 3

= 41