Four cubes of edges 5cm each are placed side by side and stuck together.if the outer surface alone is painted at 300 rupees per metre squre,find the cost of painting.
RahulRoy11:
plz solve it
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Answered by
37
If two cubes are joined, then the resultant shape will be a cuboid and the length of that cuboid will be twice the edge of each cube,breadth and height are the edge of cube.
Therefore,the length of the cuboid(l)=2*5=10cm
Breadth of the cuboid(b)=5cm
Height of the cuboid(h)=5cm
Total surface area of the cuboid=2[lb+bh+lh]
=2[(10*5)+(5*5)+(10*5)]
=2(50+25+50)
=2(125)
=250 sq.cm.
Cost of painting=250(300)=Rs.75,000.
Therefore,the length of the cuboid(l)=2*5=10cm
Breadth of the cuboid(b)=5cm
Height of the cuboid(h)=5cm
Total surface area of the cuboid=2[lb+bh+lh]
=2[(10*5)+(5*5)+(10*5)]
=2(50+25+50)
=2(125)
=250 sq.cm.
Cost of painting=250(300)=Rs.75,000.
its cost is 30 rupees per meter square
But it is given 300 in the question
so take it 300 but it is metre square
Answered by
47
if 4 cubes of 5cm are joined then a cuboid of length 20cm , breadth 5cm and height 5cm is formed
TSA of cuboid =2(lb+lh+bh)
=2{20*5)+(20*5)+(5*5)
=2{100+100+25}
=2(225)
=450 cm2
the cost of painting 1 square meter = Rs 300
the cost of painting the cuboid = 450*300
=Rs 135000
the cost of painting the cuboid is 135000
TSA of cuboid =2(lb+lh+bh)
=2{20*5)+(20*5)+(5*5)
=2{100+100+25}
=2(225)
=450 cm2
the cost of painting 1 square meter = Rs 300
the cost of painting the cuboid = 450*300
=Rs 135000
the cost of painting the cuboid is 135000
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