If (x+a) is a factor of 2x 2 + 2ax +5x + 10, find a.
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firstly,divide2x 2+ 2ax +5x +10 by x+a
REMAINDER will be (10 -5a)
so,
10 -5a = 0
-5a = -10
5a = 10
a =10 / 5
therefore, a = 2
REMAINDER will be (10 -5a)
so,
10 -5a = 0
-5a = -10
5a = 10
a =10 / 5
therefore, a = 2
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