Physics, asked by abhiramsai95, 9 months ago

four equal masses 'm' lie at the corners of a triangle of with a and length be. the CM of the system is at a) (a,b). b) (a/2,b/2). c) (b/2,a/2). d) (b,a).​

Answers

Answered by gowrisankar443
3

Answer:(a/2,b/2)

Explanation:

Answered by wajahatkincsem
0

Thus the centre of mass of the system lies at the centre of the triangle.

Explanation:

  • Since the masses are equal and all the masses are arranged symmetric to diagonal point.
  • Because all the masses are equal in distance from the diagonal mid point of the triangle.
  • Also from the center of the rectangle hence the center of mass lies on the center of the rectangle.
  • Thus the centre of mass of the system lies at the centre of the triangle.
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