four equal point charges each 20muc are placed on the four corners of a square of side 0.6m calculate the force on any one of the charge
Answers
Answer:
I didnot understand beacause I am in 6
Step-by-step explanation:
Suppose,the
4
like charges are present at
A
,
B
,
C
,
D
and
A
B
=
B
C
=
C
D
=
D
A
=
0.2
m
We are considering forces on
B
;so due to
A
and
C
force(
F
) will be repulsive in nature along
A
B
and
C
B
respectively.
due to
D
force (
F
'
) will also be repulsive in nature acting along diagonal
D
B
D
B
=
0.2
√
2
m
So,
F
=
9
⋅
10
9
⋅
(
16
⋅
10
−
6
)
2
(
0.2
)
2
=
57.6
N
and
F
'
=
9
⋅
10
9
⋅
(
16
⋅
10
−
6
)
2
(
0.2
√
2
)
2
=
28.8
N
now,
F
'
makes an angle of
45
∘
with both
A
B
and
C
B
.
so,component of
F
'
along two perpendicular direction i.e
A
B
and
C
B
will be
28.8
cos
45
So,we have two forces of
(
57.6
+
28.8
cos
45
)
=
77.95
N
acting perpendicular to each other on the charge at
B
So,net force on the charge at
B
is
√
77.95
2
+
77.95
2
=
77.95
√
2
=
110.24
N
making an angle of
45
∘
w.r.t
A
B
and
C
B