Four equal point charges each of 16 µC are placed on the four corners of the square of side 20 cm. Calculate the force on any one of the charge.
Answers
Answered by
3
Answer:
Suppose,the
4
like charges are present at
A
,
B
,
C
,
D
and
A
B
=
B
C
=
C
D
=
D
A
=
0.2
m
We are considering forces on
B
;so due to
A
and
C
force(
F
) will be repulsive in nature along
A
B
and
C
B
respectively.
due to
D
force (
F
'
) will also be repulsive in nature acting along diagonal
D
B
D
B
=
0.2
√
2
m
So,
F
=
9
⋅
10
9
⋅
(
16
⋅
10
−
6
)
2
(
0.2
)
2
=
57.6
N
and
F
'
=
9
⋅
10
9
⋅
(
16
⋅
10
−
6
)
2
(
0.2
√
2
)
2
=
28.8
N
now,
F
'
makes an angle of
45
∘
with both
A
B
and
C
B
.
so,component of
F
'
along two perpendicular direction i.e
A
B
and
C
B
will be
28.8
cos
45
So,we have two forces of
(
57.6
+
28.8
cos
45
)
=
77.95
N
acting perpendicular to each other on the charge at
B
So,net force on the charge at
B
is
√
77.95
2
+
77.95
2
=
77.95
√
2
=
110.24
N
making an angle of
45
∘
w.r.t
A
B
and
C
B
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