four forces of magnitude p,2p,3p,4p act along the four sides of a square abcd in cyclic order.use the vector kethod to find the resultant force
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the resultant of forces along AB and CD : p - 3p = - 2p = P
this is along CD direction
resultant of forces along BC and DA : 2p - 4p = - 2p = Q
this is along DA direction.
since P and Q are equal in magnitude and are perpendicular to each other , it is easy to find the resultant.
The resultant of forces P and Q will be √2 2 p
the direction is 45 deg. to either DA or BA.
this is along CD direction
resultant of forces along BC and DA : 2p - 4p = - 2p = Q
this is along DA direction.
since P and Q are equal in magnitude and are perpendicular to each other , it is easy to find the resultant.
The resultant of forces P and Q will be √2 2 p
the direction is 45 deg. to either DA or BA.
kvnmurty:
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Answered by
125
Please check attachment for detailed solution.
We have used the triangle law of vector addition in 2nd method.
It also gave the same magnitude as 2√2p and direction as 45° from AB or DA. (or 225° we can say from initial vector AB .)
Hope it helped.
Thanks
We have used the triangle law of vector addition in 2nd method.
It also gave the same magnitude as 2√2p and direction as 45° from AB or DA. (or 225° we can say from initial vector AB .)
Hope it helped.
Thanks
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