Question

Four gases He, CH4, H2 and CO2 have Henry’s constant values 69.16, 144.97, 0.413 and 1.67 respectively. The gas which is more soluble in liquid is.......

Answer 1

Given :

Values of Henry's constant for four gases is given by

• He : 69.14
• CH₄ = 144.97
• H₂ = 0.413
• CO₂ = 1.67

To Find :

Order of solubilities in liquid.

Solution :

❒ Solubility of a substance is its maximum amount that can be dissolved in a specified amount of solvent at a specified temperature.

» Pressure is a factor which affects solubility of a gas in a liquid.

• Henry's law states that “the partial pressure of the gas in vapour phase (p) is proportional to the mole fraction of the gas (x) in the solution.

$\dag\:\underline{\boxed{\bf{\orange{p=K_H\cdot x}}}}$

where $\sf{K_H}$ is the Henry's constant and is different for different gases at a particular temperature.

• Higher the value of $\sf{K_H}$ at a given pressure, the lower is the solubility of the gas in the liquid.

♦ Correct order of solubilities :

• CH₄ < He < CO₂ < H₂

Answer 2

Given :

Values of Henry's constant for four gases is given by

He : 69.14

CH₄ = 144.97

H₂ = 0.413

CO₂ = 1.67

To Find :

Order of solubilities in liquid.

Solution :

❒ Solubility of a substance is its maximum amount that can be dissolved in a specified amount of solvent at a specified temperature.

» Pressure is a factor which affects solubility of a gas in a liquid.

Henry's law states that “the partial pressure of the gas in vapour phase (p) is proportional to the mole fraction of the gas (x) in the solution.

$\dag\:\underline{\boxed{\bf{\orange{p=K_H\cdot x}}}}$

where $\sf{K_H}$ is the Henry's constant and is different for different gases at a particular temperature.

Higher the value of $\sf{K_H}$ at a given pressure, the lower is the solubility of the gas in the liquid.

♦ Correct order of solubilities :

CH₄ < He < CO₂ < H₂