four grams of hydrocarbon on complete combustion gave 12.57 grams of CO2 and 5.143 grams of water what is the empirical formula
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Answer:
hello dear,
Explanation:
C
x
H
y
+(x+
4
y
)O
2
⟶xCO
2
+
2
y
H
2
O
1 mole of C
x
H
y
gives x moles of CO
2
Given
12x+y
4
moles of C
x
H
y
gives
44
12
moles of CO
2
∴
12x+y
4x
=
44
12
or, 8x=3y
⇒
y
x
=
8
3
Therefore, Empirical formula of the hydrocarbon is C 3 H 8
.
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