Question

four grams of hydrocarbon on complete combustion gave 12.57 grams of CO2 and 5.143 grams of water what is the empirical formula​

Answer 1

Answer:

hello dear,

Explanation:

C  

x

​  

H  

y

​  

+(x+  

4

y

​  

)O  

2

​  

⟶xCO  

2

​  

+  

2

y

​  

H  

2

​  

O

1 mole of C  

x

​  

H  

y

​  

 gives x moles of CO  

2

​  

 

Given  

12x+y

4

​  

 moles of C  

x

​  

H  

y

​  

 gives  

44

12

​  

 moles of CO  

2

​  

 

∴  

12x+y

4x

​  

=  

44

12

​  

 

or, 8x=3y

⇒  

y

x

​  

=  

8

3

​  

 

Therefore, Empirical formula of the hydrocarbon is C  3 ​  H  8

​  

 .