Four holes of radius R are cut from a thin square plate of side 4R and mass M . the moment of inertia of the remaining portion about z axis is??
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according to parallel axis therom moment of inertia =product of mass of body and perpendicular distance between two parallel axis
Let us take an axis passing through center of any circle parallel to z-axis then tha distance between them will be 0.414R
then moment of inertia the body =m×0.414×R
Let us take an axis passing through center of any circle parallel to z-axis then tha distance between them will be 0.414R
then moment of inertia the body =m×0.414×R
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Your answer is (8/3-10 pi/16)MR^2
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