Question

Four identical particles of mass 1kg are arranged at the corners of a square of side length 2Root 2m if one of the particle is removed the shift in centre of mass is

Answer 1

Answer:

2/3

Explanation:

Suppose 4 partcles are at (0,2√2) (2√2,0) , (0,0) (2√2,2√2) as side of square is 1m

Centre of mass will be at (√2,√2)due to symmetry i.e. at centre of square

Suppose particle at (2√2,2√2) is removed, then coordinates of Centre of Mass are:

x-coordinate = (m1x1 +m2x2 +m3x3)/3

= 2√2/3

y-coordinate = 2√2/3

So shift = √ { (√2 - 2√2/3)^2 + (√2 - 2√2/3)^2}

= 2/3

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