Question

Four identical resistors each of R=4 are joined in a circuit as shown in the figure
given below. The cell B has e.m.f. of 2 volt and its internal resistance is negligible. Then
find out current which will read by an ammeter A.
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Answer 1

Answer:

2 Ampere {Please mark this answer as the brainliest if it helps}

Explanation:

The potential difference will be the same for all the resistors so the effective resistance would be =R/4 (Parallel circuit)

By Ohm's Law,

V=IR

=>2=I x R/4

=>I=8/R    Ampere

R=4 ohms , so I=8/R=2 Ampere

So the ammeter will show 8/R = 2 Ampere

Answer 2

Answer:

3/8 Amperes is rightr answer

Explanation:

If we redraw the diagram three resistors will be parallel and and one resistor is in the series.

so

Rep=4/3R

Res= 4R

Re= Rep+Res

Re= 4/3+4

Re=16/3

now

I= V/R

I= 2 x 3/16

I=3/8 amperes