Question

Four integers are added to a group of integers 3,4,5,5 and 8 and the mean, median, and
de of the data increases by 1 each. What is the greatest integer in the new group of
integers?​

Answer 1

Answer:Mean=(3+4+5+5+8)÷5=25÷5=5

Median=5

Mode=5(as 5 has frequency 2)

four integers are added to a group of integers

data increases by 1 each so

Mode=6

In group of integers 6 must be 3 times,So

Let fourth integer=x

Group of integers=3,4,5,5,6,6,6,8 and x

So new mean is 6

(3+4+5+5+6+6+6+8+x)÷9=6

(43+x)÷9=6

43+x=54

x=54-43

x=11

Answer-11 is the greatest integer in the new group of integers.

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