Question

four lakh, eighteen thousand and eleven​

Answer 1

Answer:

Answer:

\huge{\underline{\underline{Given→}}}

Given→

\sf\green{A.P=3,9,15,........}A.P=3,9,15,........

\huge{\underline{\underline{To\:Find→}}}

ToFind→

\sf\purple{→20th\:term\:of\:the\:given\:A.P}→20thtermofthegivenA.P

\huge{\underline{\underline{Answer→}}}

Answer→

a=3a=3

d=6d=6

\sf{\underline{\underline{\red{\implies{For\:20th\:term:-}}}}}

⟹For20thterm:−

an=a+(n-1)d

\sf\blue{→an=a+(n-1)d}→an=a+(n−1)d

\sf\blue{→a20=a+(20-1)d}→a20=a+(20−1)d

\sf\blue{→a20=a+19d}→a20=a+19d

\sf\blue{→a20=3+19(6)}→a20=3+19(6)

\sf\blue{→a20=3+114}→a20=3+114

\sf\blue{→a20=117}→a20=117

\sf{\boxed{\boxed{\pink{→a20=117✔}}}}

→a20=117✔

→→ So the 20th term of the given A.P is 117 which is the required answer.

HOPE IT HELPS.