Question

Four marks questions:
1X4=4
10. Check whether the equation 5x²-6x-2=0 has real roots and if it has,
find them by factorization method, also verify in the given equation.​

Answer 1

X = (-b +-(√b^2- 4ac))/ 2a

where b= -6 ,a= 5 ,c=-2

x=-(-6) +- (√(-6)^2 - 4×5×-2)/2×5

=6 +- (√36+40)/10

=6+- (√76/10)

x = 6+√76/10

OR

x= 6- √76/10

Answer 2

Step-by-step explanation:

Compare equation with general form

$ax {}^{2} + bx + c = 0$

a= 5

b= -6

c= 2

Find value of

${b}^{2} - 4ac$

$- 6 {}^{2} - 4(5)(2)$

= 36 - 20x2

= 36 - 40

= -4

Nature of roots is not real.