four metals are arranged according to the decreasing tendency Fo liberating hydrogen gas from dilute acid as follows: Ca,Zn,Fe,(H),Cu.In which of the following cases will a precipitate of the less reactive metal be obtained?
Answers
Answered by
15
Answer:
eith cu that is copper.
- cu, therefore is correct.
Answered by
0
In the following case, a precipitate of the less reactive metal will be obtained a) When zinc is added to an aqueous solution of copper sulfate.
- The more reactive the metal, the higher is its tendency to release hydrogen gas.
- The reactivity of the given metals is: Ca > Zn > Fe > (H) > Cu
- Only metals that are more reactive than hydrogen can liberate hydrogen gas from the solution. Hence copper cannot release H₂ (g).
- Only a more reactive metal can displace a less reactive metal from its salt solution.
- When zinc is added to CuSO₄ (aq), Zn displaces Cu from its solution, and a precipitate of Cu (s) is obtained.
- In all other options, a less reactive metal is added to the salt solution of a more reactive metal.
(The complete question is: Four metals are arranged according to the decreasing tendency of liberating hydrogen gas from dilute acid as follows: Ca, Zn, Fe,(H), Cu. In which of the following cases will a precipitate of the less reactive metal be obtained?
a) When zinc is added to an aqueous solution of copper sulfate
b) When iron is added to an aqueous solution of calcium chloride
c) When copper is added to an aqueous solution of calcium chloride
d) When iron is added to an aqueous solution of zinc sulfate.)
Similar questions