Four moles of a gas enclosed in a container is
heated at constant pressure. The temperature of
the gas increases by 3°C. The work done by the
gas is (R = gas constant).
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Answered by
35
Answer:
Work done = 12R where R is the gas constant
Explanation:
Formula for calculating any changes in a gas under certain conditions is;
PV = nRT
When a gas is heated, it means work is done on it. This work can be calculated as ;
W = ∫▒PV dv
W = ∫▒〖nRT 〗 dt dv
W = nR∆T
Now putting the values;
W = 4 x R x 3
Work done = 12R where R is the gas constant
Answered by
2
Answer:
4) 12R
Explanation:
W = nR∆T
Gn, n= 4 and ∆T = 3
W= 4R × 3
W= 12R
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