Question

Four numbers are in A.P. whose sum is 20, product of the first and fourth is to the product ofthe second and
third is 2:3, then the largest number of this A.P is equal to​

Answer 1

Answer:

let ap be a-2d,a-d,a+d,a+2d

a-2d+(a-d)+(a+d)+a+2d=20

4a=20

a=5

Step-by-step explanation:

since, a-2d×a+2d:a+d×a-d=2:3

a^2-4d^2:a^2-d^2=2:3

25-4d^2:25-d^2=2:3

125-12d^2=50-2d^2

75=10d^2

7.5=d^2

√7.5=d

so the largest no. in AP is

5+2√7.5