Question

The sum of magnitudes of two forces acting at a point is
16 and magnitude of their resultant is 8V3. If the
resultant is at 90° with the force of smaller magnitude,
then two forces are
(a) 3,13 (b) 2, 14 (c) 5,11 (d) 4, 12​

Answer 1

Explanation:

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Answer 2

Answer:

c) 6N, 10N

Explanation:

Let the smaller of the two forces is of magnitude be  F  N.

Hence the larger one will be  ( 16 − F )  N.

As the resultant  8  N is perpendicular to  F.

So, we form a right angle triangle.

By pythagoras theorem,

(16-f)^2-f^2=8^2

 (16-f)^2-f^2=64

16^2+f^2-32f-f^2=64

16(16-2f)=64

256-32f=64

F=256-64/32

F=6N

The smaller force is 6 N.

The larger force will be 16 - F

= 16 - 6

= 10 N