Four particles of mass 1kg,2kg,3kg,and 4 kg are placed at the four vertices a,b,c,d, of square of side 1 m find the position of centre of mass of the particles
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1 kg at (0,0)
2 kg at (0,2)
3 kg at (1,2)
4 kg at (1,0)
total mass = 10 kg
xcg = (1/10)(1*0 +2*0 + 3*1 +4*1) = 7/10
ycg = (1/10)(1*0 +2*2 + 3*2 +4*0) = 1
2 kg at (0,2)
3 kg at (1,2)
4 kg at (1,0)
total mass = 10 kg
xcg = (1/10)(1*0 +2*0 + 3*1 +4*1) = 7/10
ycg = (1/10)(1*0 +2*2 + 3*2 +4*0) = 1
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