Math, asked by khushid2309, 10 months ago


Four people A, B, C and D are playing a game. Each of them starts with a different number of
points. At the end of each round, one winner is declared. Each of the other three players gives
exactly half his points to the winner. After three rounds, the scores for A, B, C and D respectively
are 42, 12, 4 and 24.
3)
Who won the first round?
1) A
2) B
3) c
4) D
Who won the second round?
1) A
2) B
3) c
4) D
5)
How many points did B have at the start of the game?
1) 14
2) 12
3) 24
4) 96

Answers

Answered by Ramankaushik
3

Answer:

1)A

3)c

4)96

:::::::::::::::::::::::::

Answered by amitnrw
15

Given :  Four people A, B, C and D are playing a game . Each Winner get half points of all other players

To Find : Who won the first round , Who won the second round  and points B had at the start of the game

Solution:

Assuming Each player always had Positive Scores only

After 3rd round

A = 42  , B = 12 , C = 4 , D = 24

=> 3rd round won by A

Before 3rd Round / After 2nd round score

A = 42 - ( 12 - 4 - 24)  = 2

B = 24

C = 8

D = 48

=> 2nd Round won by D

Before 2nd Round / After 1st round score

D = 48 - ( 2 - 8 - 24)  = 14

A = 4

B = 48

C = 16

=> 1st round won by B

=> Before 1st Round / at start of the Game score

B = 48 - ( 14 - 4 - 16) = 14

A = 8

C = 32

D = 28

B  won the first round

D won the second round

B had 14 point at Start of the Game

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