four people A,B,C and D of masses 7, 9, 5, and 13 (in kg) respectively are moving with their respective velocities in the ratio 4:3:5:2. who will have the highest monument
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Answer:
momentum (p)=mv
let the common multiple be x therefore the velocity of A is 4x km/hr and B is 3x kmph c..........
now mass of A is 7 kg so momentum is mv=28x
B=27x
C=25x
D=26x
here we can see the momentum of A is greater than others
so A is your answer
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