four person jointly lift a 250kg to 1m height. how much work is done in lifting?
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Answered by
5
workdone = f×s
but if the person is on earth...then we can take a= 9.8m/s^2
so....w= 250×9.8×1
w=. 2450 j
or. w=. 2.45kj
but if the person is on earth...then we can take a= 9.8m/s^2
so....w= 250×9.8×1
w=. 2450 j
or. w=. 2.45kj
Answered by
2
Work done = Force × Displacement
= [250 kg × 9.8 m/s^2] × 1 m
= 2450 Joules
= [250 kg × 9.8 m/s^2] × 1 m
= 2450 Joules
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