Four persons p,q,r and s are initially at the four corners of a square of side 'd' . each person moves with a constant speed "v" in such a way that p always moves directly towards q, q toewards r r towards s and s towards p . after what time will the four persons meet ??
Answers
Answered by
222
Hii,
t=d/v(1-cos2π/n)
Where n is the no. Of persons
t=d/v(1-cos2π/4)
t=d/v[1-(cos90°)]
t=d/v(1-0)
t=d/v
Answered by
158
situation shown in figure. actually, every time the persons are approaching each other and hence they are moving closer and closer as they continue walking. finally they will meet at the centre of square.
from diagram, we find resultant displacement by each other when they meet will be d/√2
and the component of velocity of each towards the final point will be v/√2 .
so, time taken = displacement/velocity
= (d/√2)/(v/√2)
= d/v
from diagram, we find resultant displacement by each other when they meet will be d/√2
and the component of velocity of each towards the final point will be v/√2 .
so, time taken = displacement/velocity
= (d/√2)/(v/√2)
= d/v
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