FOUR POINTS A(6,3),B(-3,5),C(4,-2)AND D(X,3X)SUCH TRIANGLE DBC BY TRIANGLE ABC=1 BY 2,FIND X
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the given coordinates of the points are A(6,3) , B(-3,5) , C(4,-2) , and D(x,3x)
therefore the area of the triangle ABC is
Area(ABC) = 1/2[ 6(5+2)-3(-2-3)+4(3-5)
=1/2[(6*7-3*(-5)+4(-2)]
=1/2(42+15-8)
= 1/2(49)
Similarly area (DBC)=14x-7
Since area of ABC and DBC =1/2
14x-7 divided by 49/2=1/2
28x-14 =49/2
28x= 14+24.5
28x= 38.5
X= 1.375
THANK YOU
therefore the area of the triangle ABC is
Area(ABC) = 1/2[ 6(5+2)-3(-2-3)+4(3-5)
=1/2[(6*7-3*(-5)+4(-2)]
=1/2(42+15-8)
= 1/2(49)
Similarly area (DBC)=14x-7
Since area of ABC and DBC =1/2
14x-7 divided by 49/2=1/2
28x-14 =49/2
28x= 14+24.5
28x= 38.5
X= 1.375
THANK YOU
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