four resistances P,Q,R,X formed a wheat stone bridge.the bridge is balanced when R=100ohm.if P and Q are interchanged the bridge balance for 121ohm.the value of x is ??
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Q / P = X / R
X = 100 Q / P
P / Q = X / 121
X = 121 P / Q
100 Q/P = 121 P / Q => Q/P = 11/10
hence X = 110 ohms as 121 * 10/11
X = 100 Q / P
P / Q = X / 121
X = 121 P / Q
100 Q/P = 121 P / Q => Q/P = 11/10
hence X = 110 ohms as 121 * 10/11
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