Four resistors of 12 ohm each are connected in parallel. Three such combinations are then connected in series. What is the total resistance? If a battery of 9V emf and negligible internal resistance is connected across the network of resistors, find the current flowing through each resistor.
Please answer immideately..........I have my exam day after tomorrow
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resistance of one combination = 12/(1+1+1+1) = 3 ohm
total resistance = 3*3 = 9 ohm
I = v/r = 9/9 = 1 amp
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