Four resistors of 8 ohm ,10 ohm ,15 ohm and 20 ohm are connected in parallel. calculate the total resistance of the circuit
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R1=8 ohm
R2= 10ohm
R3= 15 ohm
R4= 20 ohm
1/R=1/R1+1/R2+1/R3+1/R4
=>1/8+1/10+1/15+1/20
=>15+12+8+6/120
=>41/120
R=120/41=2.926 ohm....
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@TeraBhalaHo
R2= 10ohm
R3= 15 ohm
R4= 20 ohm
1/R=1/R1+1/R2+1/R3+1/R4
=>1/8+1/10+1/15+1/20
=>15+12+8+6/120
=>41/120
R=120/41=2.926 ohm....
Hope it helps u...
If yes, mark brainliest...
have a gr8 day ahead...
@TeraBhalaHo
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