Question

Four solution for 2x+3y=0

Answer 1

Answer:

Let us take 3 cases x=3,5,7

If x=3

2x+3y=0

y=-2x÷3

y=-6÷3

y=-2

If x=5

y=-2x÷3

y=-10÷3

y=3.34

If x=6

y=-2x÷3

y=-12÷3

y=-4

hope it helps!!

#answerwithquality & #BAL

Answer 2

Given : 2x + 3y =  0

To Find : Four Possible solution

Solution:

ax + by = c is Equation of a line where a , b ∈ R  and √a² + b²  ≠ 0

Such line has infinite points  on the line

Hence Equation has infinite solution

2x + 3y =  0

a = 2 , b = 3 , c =  0   and √2² + 3²  ≠ 0

Hence Infinite solution :

2x + 3y =  0

=> 3y = - 2x

=> y = - 2x/3

x = 0  => y = 0

x = - 3 => y  = 2

x = 3  => y = - 2

x = 6 => y = - 4

Few of possible solution

( 0 , 0) , ( -3 , 2), ( 3 , - 2) and ( 6 , - 4)

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