four teams a, b, c and d participated in a tournament of Kabaddi.Each team played 2 matches to each other team. d was defeated by c two times while c was defeated by a 2 times. b won one match each from a, c and d. d defeated a for Once. d win only two matches in the hold tournament. who was the winner of the tournament
Answers
A won 4 matches .
B and c won 3 matches .
D won 2 matches .
Answer: B wins
Total matches played = 4 x 3 x 2 = 12
If we plus 1 for win and subtract 1 for loss, then the scores will be calculated line by line as
d was defeated by c two times => d -2 and c +2
c was defeated by a 2 times => (c+2) -2 and a +2
b won one match each from a, c and d => b + 1+1+1, a +2-1, c - 1, d-2 -1
= b+3, a+1, c-1, d-3
d defeated a for Once = d-3+1 and a+1 -1
= d-2 and a
d win only two matches in the whole tournament = d-2=1 = d-1
b won one match each from a, c and d which means second match a,c,d won from b => a+1 , c, d and b+2
Therefore, the final scores are a+1 , c, d and b+2 after all the matches,.
Hence, B is the winner of the tournament.