Question

Four time a number (x) exceeds two times another number (y) by sixteen (16). Seven (7) times the number (y) is 43 greater than five (5) times the number (x). Find the value of x and y

Answer 1

Step-by-step explanation:

first frame the equations

4x=2y+16

5x+43=7y

or

4x-2y=16......I ×5 = 20x-10y=70

5x-7y=-43.....II ×4 = 20x-28y=-172

use simultaneous equations and solve it

20x-10y=70

-20x+28y=172

28y-10y=172+70

18y=242

y=243/18

get y...substitute it in one equation and get x