Question

Four time the sum of two number is 140. The difference between greater and smaller is 13.The numbers are​

Answer 1

Step-by-step explanation:

Given :-

Four time the sum of two number is 140. The difference between greater and smaller is 13.

To find :-

Find the numbers ?

Solution:-

Let the two numbers be X and Y

Where X > Y

The bigger number = X

The smaller number = Y

Given that

Four time the sum of two number = 140

=> 4 ( X + Y ) = 140

=> X + Y = 140/4

=> X + Y = 35 ----------(1)

And

The difference between greater and smaller= 13

=> X - Y = 13 ----------(2)

On adding (1)&(2) then

X + Y = 35

X - Y = 13

(+)

__________

2 X + 0 = 48

__________

=> 2X = 48

=> X = 48/2

=> X = 24

On Substituting the value of X in (2) then

24 - Y = 13

=> 24 = Y+13

=> Y = 24 - 13

=> Y = 11

Therefore, X = 24 and Y = 11

Answer:-

The required two numbers are 24 and 11

Check :-

The two numbers are 24 and 11

Four time the sum of two numbers

=> 4×(24+11)

=> 4×35

=> 140

and

Their difference = 24-11 = 13

Verified the given relations in the given problem.

Used Method:-

• Method of Elimination